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CTET Sept 2016 Paper ll Lesson-3 (in Hindi)
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This lesson contain solutions with proper explanations for question number 17 to 23 of CTET Sept 2016 Paper ll " Mathematics section"

Mayank Agnihotri
B.Tech (ECE), Machine enthusiast, Inspired by an old hindi saying " Gyan baatne se badhta ha"

U
Unacademy user
awesome summary ll love to watch it again and again to fill me with will power,thanks roman sir.
  1. CTET sept 2016 Paper lI Lesson - 3 BY MAYANK AGNIHOTRI


  2. Ques 17. Abhi is twice as old as his daughter. Five years ago, his age was four times his daughter's age. If the present age of the daughter is x years, then (1) 2(x 5)-4(2x 5) (2) 2(x 5) 4(2x 5) (3) 4(x-5) = 2x-5 (4) 4(x 5)-2(2x - 5) So Let the present age of Abhi be y years Then, y-2x .) Five years ago, y-5 = 4(x-5) Putting the value of y from Eq() in Eq (I), we get,4(r-5)2x-5 [ present age of daughter is given = 01)


  3. Ques 18 A sum of 6250 Rs at 8% per annum, compounded annually, after 2-yr amounts to (1) 7165.60 Rs (2) 7872.60 Rs (3) 7581.40 Rs (4) 7727.40 Rs Sol When time is in mixed fraction, like A- Then, Amount P1 100 Here A=2 & =-. R= 8% & P=6250 Rs )2 x (1 + 1m/ = 6250 1081 2 100 )2 (1 + 0) Amount = 6250 1 +-- 100 100 100 2 (106 108100 6250 ( 100 108 108 106 = 6250 - =7727.40 Rs Ans 100 100 100


  4. Ques 19. A person marks his goods 40% above the cost price and allows 40% discount on the marked price. His loss/gain percent is (1) loss, 8% (2) No loss/gain (3) gain, 10% (4) loss, 16% So Let the cost price be 100 Rs. Then, marked price-100 + 40% of 100 = 100 +-- 100 = 140 Rs Selling prices 40% discount on MRP 100 = 140-40x140-140-56-84 Rs 100 -, SP = 84 Rs , SP < CP, There is a loss . Loss percentage = CP-SP 100=100004 100=16% Loss Ans


  5. Ques 20. The angles of a quadrilateral are in the ratio 2: 3:5: 8. The sum of the supplement of the largest angle and the complement of the smallest angle is (1) 50 (2) 80 (3) 40 (4) 70 So et 2x, 3x, 5x and 8x be the angles of the quadrilateral. sum of all the four angles of a quadrilateral = 360 2x + 3x + 5x + 8x = 360 18x 360 360 x=_=20 18 Now, smallest angle 2x 2 x 20 40 Complement of the smallest angle - 90 - 4050 Largest angle8x8 x 20 160 Supplement of the largest angle= 180 -160 -20 Required sum 20 50 70 Ans


  6. Ques 21. Two sides of a right triangle measure 15 cm and 17 cm. Which of the following statements can be true for the length of the third side of the triangle? A. It is between 4 cm and 7 cm B. It is between 20 cm and 23 cm C. It is less than 10 cm. (1) Only B (2) A and C (3) A and B (4) B and C So In a right triangle, measure of two sides are 15 cm and 17 cm Let the 3rd side of the triangle be 'x' cm Now, there are two cases, (i) When third side is not Hypotenuse (15)2 + X2 (17)2 225 + x2 289 [ By Pythagoras theorem] x = 8cm (ii) When third side is Hypotenuse (15)2 + (17)2 = X2 225 289- x2 x" [ By Pythagoras theorem] 514 V514 22.67 cm So, statement B and C are true


  7. Ques 22. If one angle of a triangle is 110 , then the angle between the bisectors of the other two angles measures (1) 90 (2) 145 (3) 100 (4) 110 Sol. Let the ABC, in which AM and CN are angle bisectors. In ABC LA + 110 + C = 180 LA + C = 180 -110 = 70 A.LC 70 35 0 2 2 Now the angle bisectors meet at 0. In 0C, + + LAOC = 180 35 ZAOC 180 40C = 180 -35 = 145 Ans


  8. Ques 23. In ABC, AB = 4 cm, AC = 5 cm and BC = 6 cm. In QR, PR = 4 cm, PQ = 5 cm and RQ = 6 cm. AABC is congruent to Sol. Scn 4on ycn 6om 6 Cm AB PR 4 cm AC PQ 5 cm BC RQ 4 cm [ By SSS Congruency]