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Answer:
- Solving x² +y² = 5 and y² = 4x simultaneously we get the value of x = 1 and -5 but we cannot take positive value so x = 1.
- Now y = 2, -2.
- P = (1,2) and Q = (1,-2)
- By distance formula we have PQ = 4.
The Circle x2 + y2 = 5 Meets the Parabola y2 = 4x at P and Q Then the Length of PQ is Equal to
Find length of PQ where circle x² + y² = 5 meets parabola y² = 4x. Step-by-step JEE and CBSE Class 11 Maths solution explained.
