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Answer: (2) 1/7
A non-leap year (or a common year) is composed of 365 days. There are 52.142857 weeks (52 weeks and 1 day) in 365 days (calculated as 365/7 = 52.142857).
As a result, there are 52 Sundays in a non-leap year. But one leftover day apart from those 52 weeks can be either a Monday, Tuesday, Wednesday, Thursday, Friday, Saturday, or a Sunday.
Probability = (Number of favourable outcomes /Total number of events)
Here, Number of favourable outcomes = 1
And, Total number of events are = 7
So, Probability = 1/7
Therefore, the probability of getting 53 sundays in a non leap year is 1/7.
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