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Answer: To find the answer to the above-mentioned problem we should find the LCM of 6,15 and 18 and then add 5.
LCM:
6 = 2 x 3
15 = 3 x 5
18= 2 x 3 x 3
LCM=90
least number =90+5=95
Therefore, answer is 95
Find the least Number which when Divided by 6, 15 and 18, Leave the Remainder 5 in each Case
Find the least number which when divided by 6, 15, and 18 leaves remainder 5. LCM-based solution for CBSE Class 6 Maths exam preparation.
