What is the oxidation number of N in NO?

Answer: The oxidation number of nitrogen in NO is +2.

Nitrogen has an atomic number of 7. The electronic configuration is as follows:

NZ=7=1s²2s²2p³

Let X be the number of times N has been oxidised.

X+-2=0

X=+2

Oxidation Number- The charge that an atom seems to have when forming ionic connections with other heteroatoms is defined as its oxidation number. A negative oxidation state is assigned to an atom with a higher electronegativity.