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Answer: n- factor is defined as the number of H+ ions replaced by 1 mole of acid in a reaction.
KMnO4.
n- factor of KMnO4,
= ½×1×(+7) – 1×(+4)1/2 = 3
In neutral medium KMnO4 forms MnO2 (+7 to +4) i.e. it gains 3 electrons. So, n- factor = 3.
What is the n Factor of KMnO4 in Basic Medium
What is the n-factor of KMnO4 in basic medium? Learn about n-factor calculation in redox reactions for CBSE Class 12 and NEET Chemistry.
