Question & Answer » Chemistry Questions » The brown ring complex compound is formulated as [Fe (H2O)5 NO]SO4. The oxidation state of iron is (a) +1 (b) +2 (c) +3 (d) +6

The brown ring complex compound is formulated as [Fe (H2O)5 NO]SO4. The oxidation state of iron is (a) +1 (b) +2 (c) +3 (d) +6

In [Fe(H2O)5NO]SO4 (brown ring complex), find oxidation state of iron. Step-by-step for CBSE Class 12 and NEET Chemistry preparation.

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Answer: The Correct option is (a) +1

A chemical test termed a nitrate test is used to identify the presence of nitrate ions in any solution. In the presence of nitrate, the liquids in the test tube create a brown ring. As a result, it’s known as the brown ring test.

The oxidation number of iron in the aforementioned compound may be calculated as follows:

[Fe (NO) (H2O)5]SO4 in water, dissociate to produce [Fe (NO) (H2O)5]2+ ions and SO42- ions.