How do you Prepare a 1 M HCl Solution, which has a specific gravity of 1.18? The HCl Solution has 35% Purity. Calculate the volume required to prepare the solution.

Answer: 

• First, we need to calculate the moles of HCl needed.

Moles of HCl  = 1L HCl×1 mol HCl1L HCl =1 mol HCl

• Second, we need to calculate the mass of HCl Needed.

Mass of HCl = 1mol HCl×36.46 g HCl1mol HCl = 36.46 g HCl 

• Third we need to calculate the mass of solution required.

Mass of solution = 36.46g HCl×100gsoln35g HCl = 104.2 g soln 

• And at last, the volume of solution required.

Volume of solution = 104.2g soln1 mL soln1.18g soln = 88 mL soln 

Therefore, the volume required to prepare the solution is 88 mL soln