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This lesson takes up various types of problems on Binomial Theorem

Vineet Loomba is teaching live on Unacademy Plus

Vineet Loomba
💥IITian | Top Educator 💥All Maths Chapters Complete & FREE 💥10+ Years Experience 💥Youtube: Maths Wallah 💥DPPs @ vineetloomba.com

U
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सर प्लीज बताये plinth to paramaount wala old एडिशन बुक कहा से ले। ओल्ड पब्लिकेशन paramount reader publication का है क्या ।please reply me sir.
Manish Kumar
3 years ago
सभी जगहों पर KD publication की मिल रही है
try kijiye old mil jaye to Baki Delhi mukhrji nagar me photocopy mil jayegi
Manish Kumar
3 years ago
sir maine flipkart se order kar liya hai . ooska price 350 hai delivery charge ke sath 450 , oosme PARAMOUNT READER PUBLICATION ka logo hai ,wahi hai kya. please confirm kijiye sir. or sir mujhe kaun sa volume lena hai. please reply sir. Thanks in advance.
Manish Kumar
3 years ago
sir mai Ranchi, Jharkhand me rahta hoo. idhar local shop me paramount ki photocopy nai milti hai. please help kijiye sir book lene me . my no. is 7979063998.
Satyam Rajput
2 years ago
sir aap free mook test ka bara ma batao
sir Iska solution https://www.instagram.com/p/B2y2XT8lad1/?igshid=17lbuyigxtrsq
sir lst exmpl nhiaya smj
sir I am unable to understand " last two digits " type question
me aap se request karta hu ki aap to bas jee ka complete syallabus cover karba dijiye.....iska matlab ye nhi ki aapki video poora syallabus cover nhi karti...mera matlab jitni aadhoori he bas unko cover karwa dijiye please sir ........................please please plesse..................................................................
Vineet Loomba
a year ago
I hope you have watched all my 28 courses on my profile ?
Viraj patel
a year ago
yes sir and i am fan of your teaching .................................................................
very good course sir, i request you to add more solved examples.
  1. SOLVED EXAMPLES BINOMIAL THEOREM JEE MAIN RANK BOOSTER COURSE PREPARED BY: ER. VINEET LOOMBA ITIAN IIT-JEE MENTOR


  2. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) ABOUT ME ** B.Tech. From IIT Roorkee -$ IIT-JEE Mentor Since 2010. -^ Doubts/Feedback in Comment Section * Comment other topics you want to revise. * Follow me @ https://unacademy.com/user/vineetloomba to get unacademy updates or search me on Google * Share among your peers as SHARING is CARING!!


  3. FOR 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Other Detailed Courses Made so far on Unacademv: V Strategy for JEE Main and Advanced V Sets, Relations and Functions V Trigonometry V Applications of Derivatives Limits, Continuity. Differentiability V Indefinite Integration V Definite Integration V Complex Number V Logarithmic Functions V Sequences Series V Most Important Questions in IIT-JEE Permutations Combinations Binomial Theorem V Straight Lines V Applications of Integrals V Circles (Detailed Course) V Probability MathematicS V Parabola (Detailed Course) v Inverse Trigonometry V Mathematical Reasoning V Ellipse (Detailed Course) V Hyperbola Upcoming Courses next month: Coordinate Geometry > Differential Equations Differential Equations MATHEMATI ER. VINEET LOOMBA (IIT RooRKee)


  4. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example # Find the number of rational terms in the expansion of (9174 + 81'6)100. SUCCESS IN JEE MAIN 2019 ER. VINEET LOOMBA (IIT RooRKEE)


  5. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) 1000 The general term in the expansion of (91/4 +81/6 IS 1000-r 1000-r r r1100C 94 The above term will be rational if exponent of 3 and 2 are integers It means2 The possible set of values of r is 0, 2, 4, 6 =1000c, 32 22 1000-r and must be integers 2 .., 1000) Hence, number of rational terms is 501 SUCCESS IN EE MAIN 2019 ER. VINEET LOOMBA (IIT RooRKEe)


  6. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Find the middle term(s) in the expansion of Y214 1 14 2 Solution: 2 14+2 th term. Here, n is even, therefore middle term is It means Ta is middle term 7 429 2 x-1 =- Ta4C, X14. Ans. 2 SUCCESS IN JEE MAIN 2019 ER. VINEET LOOMBA (IIT RooRKEE)


  7. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) th&M.1)th Solution Here, n is odd therefore, middle terms are l- - 2 It means T. & T are middle terms 4 189 aAns T6 = 9C5 (3a)9-51-6. a19. Ans 16 SUCCESS IN EE MAIN 2019 ER. VINEET LOOMBA (IIT RooRKEe)


  8. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example # Find the numerically greatest term in the expansion of (3 - 5x)" when x-5. Solution. Let rth and (r1)th be two consecutive terms in the expansion of (3-5x)15 T., 2T 3.(15)! (15-r)!r! 5. 5 (16-r)23r 16-r23r4rs 16 rs 4 SUCCESS IN JEE MAIN 2019 ER. VINEET LOOMBA (IIT RooRKEE)


  9. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example # Find the last two digits of the number (17)1 Solution. (17)'0(289)5 = (290-1)5 - A multiple of 1000 1449 Hence, last two digits are 49 SUCCESS IN JEE MAIN 2019 ER. VINEET LOOMBA (IIT RooRKEE)


  10. 100% SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Example # If x is so small such that its square and higher powers may be neglected (1- -3x)1'2 +(1-x)513 then find the value of (4 +x) 1/2 Solution 513 (4+x) 1/2 4 2 x 19 812 x Ans. 24 SUCCESS IN EE MAIN 2019 ER. VINEET LOOMBA (IIT RooRKEe)