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Pipe and Tank - Part 3 (in Malayalam )
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This lesson discusses about the problems related to pipe and tank

Akhil A S is teaching live on Unacademy Plus

Akhil A S
> More than 6 six years experience in PSC field > Cracked different exams like ALP,Excise > Fb page and Telegram group - PSC Challenger

U
Unacademy user
I didn't understand 5th questions last step. how 15/5 came? before birth of youngest member, AVG= 22-7= 15 (n=6) but no of members were originally 5 only. at the birth of youngest member, n=6 then their average may reduce na?
Anoop C
2 years ago
sir, avg of 6 at present=22 avg of 6 seven yrs back=22-7=15 total age of 6 seven yrs back=15*6 but 7yrs back only 5 members then avg=(15*6)/5=18
Rahul gosam
a year ago
avg means it distributes to all R8.. then the 15 yrs of that youngest one (who is not born 7 yrs ago ) shouldn't be counted that implies this 15 yrs distributes to 5 mem of family that's where 15+15/5 comes.. hope u understood..
THANK YOU SO MUCH SIR..............
enik kityath 60/7minutes aaanu
Akhil A S
8 months ago
Yes
Akhil PS
8 months ago
athalle correct
60/7 anu kittunne .reciprocal aduthilla
athalle right answer
  1. MISSION UNIVERSITY ASSISTANT QUANTITATIVE APTITUDE PIPE AND TANK PART3 Prepared by : AKHILA S/ unacademy


  2. Q. A tanh has tnee inlet- valves P.aR tfill in Uwa tanh cill b fi llcd n S houss, 3 hours aod 2 hours Values 7e_ has 620 63Dl Gx3+ 3x2 +6x2 I8 +6+1 2 86=1


  3. Q. Two and thind tap can ea opened ee-taps are- at-the same-bma , how 3d 10 2 12 s