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5 lessons,
44m 18s
Phy NEET 11-01
3,147 plays

When a plate is inserted within a capacitor its capacity changes. All other associated quantities like voltage, charge and energy change. how do they behave is explained in this question.

Pradeep Kshetrapal is teaching live on Unacademy Plus

Pradeep Kshetrapal
State topper in school exams, selected in IIT Kharagpur, M.Sc., 30 yrs in teaching.

Unacademy user
How can I download its taking alot buffering
ye aiims 2017 ka question h .....a charge of 12 pC placed at distance of 10 cm directly above the centre of a square of side 20cm . what is the magnitude of electric flux through the square? pls smja do sir.....pls
thnq sir aap mil gue
Pradeep Kshetrapal
9 months ago
God bless you.
8 months ago
explain in board please please
Force is a attraction or repulsion that any charge particle or body experience and electric field is basically the effect of force around charge charge particle
What is the difference between force and electric field
And are this Equations comparable F=ma and F=qE
  1. NEET PHYSICS by Pradeep kshetrapal

  2. Current Electricity Lesson no. NEET-PHY-11-01

  3. A Parallel plate cacacitor of capacitance C is connected to a cell of emf V and then disconnected from it. A dielectric slab of dielectric constant K which can just full the air gap os the capacitor is now inserted in it. Which of the following is incorrect..

  4. (a) The potential difference the plates deceases K times. (b) The energy stored in the capacitor decrease K times 2 -1) (c) The change in energy stored is CV (d) The charge on the capacitor is now conserved

  5. When battery is disconnected, the path of charge travel (in and out) is closed. Hence charge become a constant quantity. This makes statement (d) as correct statement.

  6. The dielectric plate insertion always increase the capacitance by K times. Now since charge q is constant and C has increased K times, the voltage-will decrease to That is statement (a) that voltage decrease K times is a KC correct statement.

  7. For calculating effect on energy we consider relation as energy stored-- This relation is taken up since q is a constant in this case ane energy depends only on C. 2C Here C has increase K times hence energy decreases K times which shows that statement (b) is correct

  8. Since statements a,b and d are discussed to be correct, the only incorrect statement remain is (c) . So that is our option for incorrect answer.. As such, we know the relation of decrease in energy to be 2 2 2 2c 2kc 2c Therefore our choice for incorrect answer is (C)

  9. Here we cannot use the relation 1 CV2( -1) because C and V both have changed. With the new values it will beV1) C (-1) which does not match with the given statement. Hence this is not correct statement. Therefore this is our choice for incorrect answer.