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Phy NEET 10-1
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Phy NEET 10-1 deals with concept of potentiometer and potential gradient by either adding the resistance or changing the length

Pradeep Kshetrapal
State topper in school exams, selected in IIT Kharagpur, M.Sc., 30 yrs in teaching.

Unacademy user
what about 2016 mcq
sr 11 m dhyan nahe dea tha or ab 12m puri mehnt kr rha hu sr buut depration m hu
Pradeep Kshetrapal
4 months ago
ट्वेल्थ में सिर्फ ट्वेल्थ का कोर्स आएगा इसलिए जो सामने है उस पर ध्यान दो पिछले को भूल जाओ मन लगाकर पढ़ो सारे फॉर्मुलस याद करो सफलता अवश्य मिलेगी
Pooja
4 months ago
luv u sirr ur godddd sir
sir sirf aapki wjh se meri physics thik hua
The best teacher ever🙏..concepts get very much clear by your lessons sir ...thank you ...keep posting
  1. NEET PHYSICS by Pradeep kshetrapal


  2. Current Eectricity Lesson no. NEET-PHY-10-01


  3. A potentiometer wire has length 4m and resistance 8Q, The resistance that must be connected in series with the wire and an accumulator of emf 2V so as to get a potential gradient 1mV per cm on (a) 32 (b) 40 (c) 4462 (d) 48


  4. AB is potentiometer wire having resistance 8 Potential gradient 1mV is potential drop per unit length, i.e. per centi-meter. Therefore across AB potential difference is 400mV Therefore current in the circuit is VAB 400x10-3 8 E- 2V 4m, 8 Potential gradient 1mV


  5. The net resistance of the circuit is 8+R potential difference is 2V and current we calculated as 5x10-2A 8R0-72 .R- 8-32. R 32 5x10-2 200 option a) 5 E= 2V 4m, 8 Potential gradient 1mV