NEET PHYSICS by Pradeep kshetrapal
Current Eectricity Lesson no. NEET-PHY-10-01
A potentiometer wire has length 4m and resistance 8Q, The resistance that must be connected in series with the wire and an accumulator of emf 2V so as to get a potential gradient 1mV per cm on (a) 32 (b) 40 (c) 4462 (d) 48
AB is potentiometer wire having resistance 8 Potential gradient 1mV is potential drop per unit length, i.e. per centi-meter. Therefore across AB potential difference is 400mV Therefore current in the circuit is VAB 400x10-3 8 E- 2V 4m, 8 Potential gradient 1mV
The net resistance of the circuit is 8+R potential difference is 2V and current we calculated as 5x10-2A 8R0-72 .R- 8-32. R 32 5x10-2 200 option a) 5 E= 2V 4m, 8 Potential gradient 1mV
State topper in school exams, selected in IIT Kharagpur, M.Sc., 30 yrs in teaching.