APPLIED MECHANICS GATE PIPAPER RECHNICAL SECTION PART 2) STRESS AND STRAIN

Tensile stress (ot) Compressive stress (Oc) Shear stress (T)

Tensile strain (Et) Compressive strain EC Shear strain (Y)

TRUE STRESS AND TRUE STRAIN Comparison of engineering and the true stress-strain curves Relation between the ultimate tensile strength and true stress at maximum load

HOOK'S LAW VOLUMETRIC STRAIN (EV YOUNG'S MODULUS OR MODULUS OF ELASTICITY (E MODULUS OF RIGIDITY OR SHEAR MODULUS OF ELASTICITY (G) BULK MODULUS OR VOLUME MODULUS OF ELASTICITY (K) -RELATIONSHIP BETWEEN THE ELASTIC CONSTANTS E, G, K, . POISSON'S RATIO ( ) FOR BI-AXIAL STRETCHING OF SHEET

A prismatic bar loaded in tension by an axial force Elongation of composite body Elongation of a tapered body Elongation of a body due to its self weight

FACTOR OF SAFETY: (N) THERMAL OR TEMPERATURE STRESS AND STRAIN .THERMAL STRESS ON BRASS AND MILD STEEL COMBINATION MAXIMUM STRESS AND ELONGATION DUE TO ROTATION ELASTICITY PLASTICITY STRAIN HARDENING STRESS REVERSAL AND STRESS-STRAIN HYSTERESIS LO0P

PRIMARY CREEP SECONDARY CREEP TERTIARY CREEP

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Indira Roy

GATE AIR 391 || Passionate about teaching

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Arun Jangid

9 months ago

sir aapke padhene ka tarika aacha laga

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Ravi Singh

8 months ago

thanks Arun

Arun Jangid

8 months ago

some more questions. please give answer.

Arun Jangid

8 months ago

If you have given the atom of X gas is equal his Avogadro's number and 1/2 atom converted X(g)+ by ∆H energy. Then find the ionsion energy of X.

Arun Jangid

8 months ago

the required energy for ionsion of 0.02g Mg atom is x kj. find the energy for ionsion of 1atom of Mg.

Ravi Singh

8 months ago

N = Avogadro number = 6.023* 10²³
Each atom gives one electron out. Half of N atoms are ionized by energy ∆H hence IE per atom is given as ΔH / (N/2) units per atom

Ravi Singh

8 months ago

no of atoms in 0.02g Mg is 0.02/24 * Avogadro's no. = 5* 10²0 and they take x kj so the energy for 1 atom is roughly x/ 5* 10²0 = x *2 * 10 power -21

Ravi Singh

8 months ago

sorry Arun for the delay but since I am busy sometimes I will add the answers as soon as I can