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Modulus and Argument of a Complex Number
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This lesson explains the concept of Modulus and argument of a complex number for JEE Main and Advanced

Vineet Loomba is teaching live on Unacademy Plus

Vineet Loomba
IITian | No. 1 Educator in IIT-JEE (Maths) | 3 Million Minutes Watch Time | 8+ Years Experience | Youtube: Maths Wallah | vineetloomba.com

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What's the loss if the fund lapse after the fiscal year ? It"ll be back in the next ... Is it possible to make it non-lapsable for single ministry ? The same situation applies for all ..
Sachin Aazad
2 years ago
fund lapse hone ke baad.....fund dubara aane ki process lambi hoti hai..to wait krna padta or fir related ministry ka kaam rukta hai.......ha single ministry ke liye ya uske kisi department ke liye non lapsable fund bna sakti hai .....
Jatin Verma
2 years ago
All the ministries are not as important as DEfence... Simple logic.... It is not as easy to get it back again... coz there is a competition among ministries to get the larger pie of the budget
Aishwarya Mishra
2 years ago
thanks to both of you .. :) @Jatin Verma exactly that's what m asking .. i mean every ministry may demand for the same as u said there is a competition among ministries.. that they must get non-lapsable fund as well. They will start showing importance of their ministries (ex. Home ministry-imp one) n ll start demanding for the same.
sir i meed 1 st year lessons also for preparation of emcet and mains
Vineet Loomba
3 months ago
All avlbl on my profile
sir ji aapki slide mai 2nd property mei ek mistake hai...vo |z1 - z2| vali mai.. bass baaki tohh best lecture tha.. loved it
Vineet Loomba
3 months ago
Kya mistake h dost ?
Pratham M
3 months ago
sir ji |z1 - z2| ≥ | |z1| - |z2| | sirf whole Mai modules Nahi laga hua tha
Sir I have a doubt on mathematical reasoning iit mains 2018
Vineet Loomba
6 months ago
Wht doubt ?? ..see the course on Mathematical reasoning
Avinash Kumar
6 months ago
Just a question of 2018 mains i am asking otherwise i know the chapter
sir please , i need course on probability . jaldi bana dijiye sir.
Vineet Loomba
9 months ago
it will take time as this is covered in last.
Rangnath Gote
9 months ago
ok
sir please suggest me mathematics book for jee main preparation
Vineet Loomba
a year ago
i ll soon add a video on books in my iitjee strategy course...follow that course
  1. IIT-JEE CRASH COURSE FOR SURE SHOT SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) Search vineet loomba unacademy" on GOOGLE IIT-JEE MATHS REVISION COURSE PREPARED BY: ER. VINEET LOOMBA IITiAN | IIT-JEE MENtoR


  2. REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE ABOUT ME B.Tech. From IIT Roorkee IIT-JEE Mentor Since 2010. Doubts/Feedback/Ideas in Comment Section. Comment other topics you want to revise. Follow me @ https://unacademy.com/user/vineetloomba to get updates. Share among your peers as SHARING is CARING !!


  3. COMPLEx NUMBERS FOR SURE SHOT SUCCESS IN JEE MAIN AND ADVANCED (IIT-JEE) #MODULUS AND ARGUMENT IIT-IEE MATHS REVISION COURSE PREPARED BY: ER. VINEET LOOMBA IITiAN | IIT-JEE MENTOR


  4. REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE MoDULUS OF A COMPLEX NUMBER The modulus, which can be interchangeably represented by orr, is the distance of the pointz from the orign, sothat its numerical value isgiven by _r_Vr'T MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)


  5. REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE Example: Find the complex numbers zwhich simultaneously satisfy the equations Solution: z-125 z-4 z-8i3 z-8 x-4+iy Here z-125 x=012-sil-3 -25y +136-0 9(364 y*)-2536 + (y-8 y = 17, 8 Hence the required numbers are z = 6 + 1 71 6 + 8 i. MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)


  6. REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE PRINCIPAL ARGUMENT OF A CoMPLEX NuMBER 2 z lies in the first quadrant z lies in the second quadrant MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)


  7. REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE PRINCIPAL ARGUMENT OF A CoMPLEX NuMBER z lies in the third quadrant 2 lies in the fourth quadrant 2 MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)


  8. REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE Method of finding the principal value of the argument ofa complex number z = x + y. Step 1 : Find tan and this gives the value of in the first quadrant. StepII: Find the quadrant in which z lies, with the help ofsign of x and y coordinates. MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)


  9. REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE b> 0, then + b > 0, then (i) If z lies in the I quadrant principal argument-6- and general argument-2 k If z lies in the II quadrant principal argument-6-7- and general argument-2 If z lies in the III quadrant principal argument-0- + and general argument-2 k + ( - ) If z lies in the IV quadrant principal argument-0- and general argument-2 k- i.e. a >0 and (ii) i.e. a < 0 and + ( - ) (iii) i.e. a < 0 and b< 0, then (iv) i.e. a> 0 and b < 0, then MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKee)


  10. REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE POLAR FORM z r (cos + i sin ) EULeR FORM z=re =cos + i sin MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)


  11. REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE PROPERTIES arg (zi . Z2 3 z") = arg (zi) + arg (z,) + + arg (z.) 2.121-211 arg()=arg (zi )-arg (:) . 4 MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)


  12. REVISION COURSE FOR JEE MAIN AND ADVANCED (IIT-JEE Example: If z-2il 2, then find the greatest and least of z Solution: we have lz _ 2 + il -12-11-11 -,51 Hence greatest value of lis 5 + 2 and least value of lis 5-2. MATHEMATICS FOR IIT-JEE ER. VINEET LOOMBA (IIT RooRKEE)