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JEE MAINS (2014-2012) : Permutation and Combination Previous Year Questions with Solution (in Hindi)
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JEE MAINS Previous year Permutation and Combination Questions with solution.

Shivam Gupta
JEE Mains and Advanced Mathematics with Shivam Sir Be maths expert with us - Aspire Study Youtube Channel NIMCET PYQs

U
Unacademy user
sare unit ke course chahiye ma'am
do person ko no ball milne wala case bhi minus hoga
do person ko no ball milne wala case bhi minus hoga
Shivam Sir...🙏🙏🙏🙏🙏 Many Students are there who can't afford coaching fee and accommodation in other Cities. but they can afford JIO net pack easily.. You are Doing Such a great Job. Please keep doing. I m NIMCET 2019 aspirant. I wanna get there in NITs. I seems possible when i see you.... Thnxxx #गुरु_जी
FARAZ
9 months ago
what is nimcet bhai
Question puchne thai aapse please tells us sir ji
Sir can you please make a similar series for all the Calculus topics like Indefinite Integration, Definite Integration, application of derivatives,etc. please sir????????
Shivam Gupta
2 years ago
I am working for this... thanks for appreciate.
  1. JEE (MAINS+Advanced) & AIEEE Previous Year Questions and Solutionn Permutation and Combination Shivam Gupta HBTU/K Follow me on Unacademy https://unacademy.com/user/shivam2k10


  2. Question: Suppose the six students, including Madhu and Puja, are having six beds arranged in a row. JEE MAIN 2014] Further, suppose that Madhu does not want a bed adjacent to Puja. Then the number of way, the beds can be allotted to student is (a) 384 (b) 264 (c) 480 (d) 600 Solution Six students, including Madhu and Puja, can be adjusted on six beds in 6! Ways Madhu and Puja, can be adjusted on two beds in 2! Ways Consider these adjacent beds as one and the remaining 4 beds can be arrange in 5! Ways. So, Madhu and Puja can be adjusted on adjacent bed is 5! x 2! ways Ways.PM Hence, Number of ways in which Puja and Madhu are not on adjacent beds= 61-51x 2! = 480


  3. Question: JEE MAIN 2013] Let T, number of all possible triangles formed by joining vertices of an n -sided regular 10, then the value of n is polygon. If Tn+1- Tn (a) 7 (b) 5 (c) 10 (d) 8 Solution Given, T, =C, Given, T,-'C "m-z = 10 n+1C3-nC,-10 C,+ C,-'C-10 C2 10 n=5


  4. Question: JEE MAIN 2013] Let A and B be two sets containing 2 elements and 4 elements, respectively. The number of subsets of A B having 3 or more elements is (a) 256 (b) 220 (c) 219 (d) 211 Solution Given, n(A) 2 and n(B) = 4 n(A B) = 8 The number of subsets of A B having 3 or more elements =28-1-8-28 219


  5. Question: The total number of ways in which 5 balls of different colours can be distributed among three IIT 2012] persons so that each person gets at least one ball is (a) 75 (b) 150 (c) 210 (d) 243 Solution Required number of ways Total number of ways in which 5 balls of different colours can be distributed among three persons Number of ways in which at least one person get no ball = 243-96 + 3 = 150