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Tamanna Chaudhary

नमस्ते 🙏
The Newton's apple. 🍎
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Ansar Ansari

7 months ago

completed this lesson.

1

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Juhi Mishra

7 months ago

good

Abhishek chauhan

10 months ago

mam do any curve line in position-time graph shows CONSTANT acceleration or only acceleration?

4

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Tamanna Chaudhary

10 months ago

Only acceleration.

Tamanna Chaudhary

10 months ago

Straight line will show constant velocity
So curve will show variable velocity (which means acceleration)

Ashish Tiwary

a year ago

a man in a ballon rising vertically with an acc of4.9 released a ball 2sec after the ballon is let go from the ground the greatest height above the ground reached by the ball [g =9.8]

2

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Tamanna Chaudhary

a year ago

We'll go step by step to make understand better-

Tamanna Chaudhary

a year ago

Step 1- We need to calculate the upward velocity of the ballon after 2seconds of It's let go-
Use equation v= u+at.
put u=0, t=2 and a= 9.8ms^-2 to get v= 9.8 m/s in upward direction.

Tamanna Chaudhary

a year ago

Step 2- Calculate the distance moved by the balloon in these 2 seconds to see from what height the ball has been dropped -
Use the equation, S= ut + 1/2(at^2)
put u=0, a=4.9 m/s^2, t= 2s.
We will get S= 9.8m

Tamanna Chaudhary

a year ago

Step 3- Now as we know the initial velocity of the ball (in the upward direction) and height from which it was thrown down, calculate the velocity with which it hit's the ground-
v^2- u^2 =2as.
Be careful about the sign conventions here.
Substitute u = -9.8m/s, S = (9.8m) and a=g to get v= (underroot 3)g

Tamanna Chaudhary

a year ago

Step 4-
Now we know the velocity with which the ball hit the ground, and we know the value to gravitational acceleration.
so use the equation again- v^2- u^2= 2as
Substitute the values along with sign conventions-
u= - (underroot 3) g
a= g
to get S= -14.7m, where negative sign signifies the distance travelled in upward direction

Ashish Tiwary

a year ago

Thanks mam

Ashish Tiwary

a year ago

Mam step 1 me a=4.9 use karnege n & a=4.9 sirf upward motion ke liye hi use krenge n

Tamanna Chaudhary

a year ago

Yes Ashish, we need to take a= 4.9m/s^2 In the first step

Almin Sayed

9 months ago

maam ques three me particle rest se start koya toh uski initial velocity 100 kaise hui???plz

1

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Tamanna Chaudhary

7 months ago

By using v^2 - u^2 = 2as equation, aapko S ki wo value nikalni hai jo object cover karega from time t to t+1, iska matlab hai ki aap is equation mein initial velocity loge time t wali and final velocity loge time t+1 wali. Agar aapko distance travelled by the toby in total time t+1s pucha hota tab aap initial velocity ko zero lete, lekin humein yahan S ki value puri journey ki nahi puchi hai sirf t se t+1 time ke beech wali puchi hai.

Umar Arshad

9 months ago

Ma'am question No 19 my app ny kesy distances find kiye Han Samjh nhi aye.. Kindly guide

0

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My

Mansi yadav

9 months ago

mam question 9 ek baar explain kar dijiye plz

0

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Musa Khan

4 months ago

Firstly that ratio of s1,s2.... given is the distance travelled in seconds like s3 is distance travelled in 3 seconds whereas s'3 is the distance travelled in particularly 3rd second.

Musa Khan

4 months ago

Firstly that ratio of s1,s2.... given is the distance travelled in seconds like s3 is distance travelled in 3 seconds whereas s'3 is the distance travelled in particularly 3rd second.

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