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Entropy Handpicked Question Series PART-3 (in Hindi)
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Question based on resistor with insulation and without insulation

Deep Sangeet Maity
->VERIFIED EDUCATOR ->DESIGN ENGINEER @ SCHLUMBERGER ->KREATRYX GATE Content Developer ->99.4%ile GATE-18

U
Unacademy user
thanku....i think anyone can learn from ur lecture..
in this question when resister was not insulated (1st phase of the question) why we can't use (delta S) resister = -Q/T hear heat is rejected that's why Q will become -ve ,,, IS NOT IT ?
hear also temperature made constant then, why we can't use this formula. (-Q/T) ?🤔🤔 why we are using the formula mcpln(T2/T1)
Deep Sangeet Maity
4 months ago
you can't use -Q/T for resistor Becoz resistor is a system(solid) for solid ∆s=m C ln(T2/T1).... and tell me if you are taking -Q/T for delta S (resistor) then what will be the surrounding's delta S
hear our system is resister Q (=i2rt) amount of heat comes from surrounding ,and by question temp of the resister made constant (that is not possible by adding heat from surrounding , after that also by the question demand it is made constant at 300 k ) then (delta s) system= Q/T and (delta s) surrounding=(that amount of heat comes to the surrounding)/(temp of surrounding) and by adding these qualities we will gate (delta s) universe Sir , is there any chance that I can send my photo copy of hand written language
this is difficult to write every symbol and confusion that happens to me at this comment box.
Deep Sangeet Maity
4 months ago
see the difference... resistor is a solid body , for resistor we need an input for getting an output.. In this case electrical energy causes Q to transfer to surrounding...so you can't use Q/T formula... Q/T formula is applicable for Infinite bodies .. Infinite body means either there is input or output like Source(Thermal reservoir) can provide heat continuously without any input to it and it's specific heat capacity is also infinite so for Infinite bodies we'll use ∆S= Q/T... Resistor is finite solid body where we need some input (in this case electrical energy) to get output.... so here ∆S = m C ln(T2/T1) will be used and T1=T2 so ∆S=0
thank you so much
thank you so much
  1. Entropy Lesson-3 GATE Presented by Deep sangeet Maity


  2. About ME Working as a Design engineer at "Cameron Manufacturing India Limited (A Schlumberger Company)". .Currently working as "GATE content editor and developer"at "Kreatryx" .Qualified GATE "3" times .Qualified "Gate 2018 with 99.4 percentile 779(75.26 marks) gate score" in mechanical stream .Qualified "Gate 2017 with 98.83 percentile 726(70 marks) gate score" irn mechanical stream I also have an 2+ years of experience of teaching Engineering subjects like Engineering mechanies, Thermodynamies, SOM, HMIT Ex-CADD Engineer at "CADD CENTRE". Passed B.E. with honours with 76.71%. I am pursuing my MTech in Thermal I have an 2.5+ years of experience as a CADD Engineer. . . also have worked for "CAD ACADEMY" as a Design engineer for 1 year.


  3. esi stor ofZoS2_ is maintained , a cou- ant emperature of 2 c ehile a cwmer- of lo A. is allosed to fo far the enhepy 1 sec. Deteymne change the , u i stor , and +he fthe ges is tor in. Holly ar 27 C mow insulated& Hhe ame cwrnenh is paused for the same time. Deton mine the enhop the umivense. The specifie heat of the resistor s 0. kJ k4K and the mas of the nesistois e of the resis or ?


  4. Sol The nesistor is no in sulated Not insulated The tompenature wll remein censta because it is ret insulted, what-em the s to the-Sam ound. resis A Sruis tor RE


  5. Now WiH inswlatiom 0A. As, insulation s thore so , be causeo & He tempe afuR will increase afte 1sec. E m -T2-632.33 K


  6. esisr - lo X 900 ln 633.33 Be cause ofins wlation ASsuornoundi Suru verse 6.72 +


  7. Rate Review Recommend https://unacademy.com/user/deepsangeet follow