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Alligation Basics
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Alligation basic formula and less - more approach to solve question of mixture

## Bharat Gupta is teaching live on Unacademy Plus

Bharat Gupta
Engineer by degree Mathematician by Heart. Having 22 years of teaching experience. Search me on Youtube for more videos.

U
mam hi purn lectures tumhi youtube var upload keli tar sarvarthane tumachyamule khup sarya marathi vidhyarthyancha fayada hoil thaks
9 months ago
Jarur sir. Lavkarach karu. Mi sadhya medical leave var ahe.
thankyou very much sir sir can't we find z directly by (ax +by)/(X+y)
thankyou very much sir sir can't we find z directly by (ax +by)/(X+y)
Ma
i still didnt understand how SP is 62 in the qstn in 11:45 seconds.
Mayank gupta
2 months ago
brother it has come as (68.20/11)*10
sir , at 11:37 , can pls explain that concept again sir . I didn't understand how 62 came there , because to calculate 10 percent of profit , i multiplied 68.20*0.9 and got 61.38 as answer . Kindly explain the concept used there sir .
Milind Singh Sidhu
10 months ago
For 10% profit , the denominator is showing the cp and 1(numerator) is the profit, so the SP =CP+ Profit. thus, 11--> 68.2 1-->68.2/11=6.2 10-->6.2*10=62 So the CP is Rs.62
Janani Sundar
10 months ago
Thank u sir..understood !!
sir why you have let 40 and why not any other number .in the last question .
1. Alligation Basics part 1 Er. Bharat Gupta

2. Alligation Percent concentration based questions Let x litre of a% acid is mixed with y litre of b% acid. Let concentration of final mixture be z%. When we mix two liquids we have following conclusions Conclusion 1: Volume of final mixture is sum of the two mixtures. Conclusion 2: Concentration of final mixture is unknown but it will lie between the two concentrations a and b. Let a > b, hence a > z> b. First mixture LI Volume of the mixtures Concentration of the mixtures 2 2 2 6%) Second misture

3. First mixture dro Volume of the mixtures Concentration of the mixtures 6%) Second mixture Note that Middle value () always comes in the diagonal position or or

4. Alligation average less more approach Percent concentration based questions Let x litre of a% acid is mixed with y litre of b% acid. Let concentration of final mixture be z%. When we mix two liquids we have following conclusions Conclusion 1: Volume of final mixture is sum of the two mixtures. Conclusion 2: Concentration of final mixture is unknown but it will lie between the two concentrations a and b. Let a > b, hence a > z> b. First Part Second Part Final Part x + y a% b% Z%

5. If 30 litre of 20% milk is mixed with 20 litre of 25% milk, then find the concentration of milk in the resulting solution. a. 21% b. 22% c. 23% d. 24%

6. If 30 litre of 20% milk is mixed with 20 litre of 25% milk, then find the concentration of milk in the resulting solution. a. 21% b. 22% c. 23% d. 24% 30 20 207. 7 20 30 -25 20 -20 2020 2b 21-20

7. If 30 litre of 20% milk is mixed with 20 litre of 25% milk, then find the concentration of milk in the resulting solution. a. 21% b. 22% c. 23% d. 24% First Part Second Part Final Part 30 3 207. 2. 50 25% 23 Cub) 2 Py

8. Two types of steel A & B are available. Type A contains 5 % Nickel and type B contains 40% Nickel. Quantity of steel B should be mixed with 20 kg of steel A so that the final alloy contains 30% Nickel? a. 20 kg b. 30 kg c. 40 kg d. 50 kg

9. Two types of steel A & B are available. Type A contains 5 % Nickel and type B contains 40% Nickel. Quantity of steel B should be mixed with 20 kg of steel A so that the final alloy contains 30% Nickel? a. 20 kg b.30 kg c. 40 kg d. 50 kg 5y Ltoy 20 20 40-3 BoV

10. Two types of steel A & B are available. Type A contains 5 % Nickel and type B contains 40% Nickel. Quantity of steel B should be mixed with 20 kg of steel A so that the final alloy contains 30% Nickel? a. 20 kg b.30 kg c. 40 kg d. 50 kg (hekod-i First Part Second Part Final Part A. 20