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Alligation Basics
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Alligation basic formula and less - more approach to solve question of mixture

Bharat Gupta is teaching live on Unacademy Plus

Bharat Gupta
Engineer by degree Mathematician by Heart. Having 22 years of teaching experience. Search me on Youtube for more videos.

U
Unacademy user
mam hi purn lectures tumhi youtube var upload keli tar sarvarthane tumachyamule khup sarya marathi vidhyarthyancha fayada hoil thaks
Soni Kadam
9 months ago
Jarur sir. Lavkarach karu. Mi sadhya medical leave var ahe.
thankyou very much sir sir can't we find z directly by (ax +by)/(X+y)
thankyou very much sir sir can't we find z directly by (ax +by)/(X+y)
Ma
i still didnt understand how SP is 62 in the qstn in 11:45 seconds.
Mayank gupta
2 months ago
brother it has come as (68.20/11)*10
sir , at 11:37 , can pls explain that concept again sir . I didn't understand how 62 came there , because to calculate 10 percent of profit , i multiplied 68.20*0.9 and got 61.38 as answer . Kindly explain the concept used there sir .
Milind Singh Sidhu
10 months ago
For 10% profit , the denominator is showing the cp and 1(numerator) is the profit, so the SP =CP+ Profit. thus, 11--> 68.2 1-->68.2/11=6.2 10-->6.2*10=62 So the CP is Rs.62
Janani Sundar
10 months ago
Thank u sir..understood !!
sir why you have let 40 and why not any other number .in the last question .
  1. Alligation Basics part 1 Er. Bharat Gupta


  2. Alligation Percent concentration based questions Let x litre of a% acid is mixed with y litre of b% acid. Let concentration of final mixture be z%. When we mix two liquids we have following conclusions Conclusion 1: Volume of final mixture is sum of the two mixtures. Conclusion 2: Concentration of final mixture is unknown but it will lie between the two concentrations a and b. Let a > b, hence a > z> b. First mixture LI Volume of the mixtures Concentration of the mixtures 2 2 2 6%) Second misture


  3. First mixture dro Volume of the mixtures Concentration of the mixtures 6%) Second mixture Note that Middle value () always comes in the diagonal position or or


  4. Alligation average less more approach Percent concentration based questions Let x litre of a% acid is mixed with y litre of b% acid. Let concentration of final mixture be z%. When we mix two liquids we have following conclusions Conclusion 1: Volume of final mixture is sum of the two mixtures. Conclusion 2: Concentration of final mixture is unknown but it will lie between the two concentrations a and b. Let a > b, hence a > z> b. First Part Second Part Final Part x + y a% b% Z%


  5. If 30 litre of 20% milk is mixed with 20 litre of 25% milk, then find the concentration of milk in the resulting solution. a. 21% b. 22% c. 23% d. 24%


  6. If 30 litre of 20% milk is mixed with 20 litre of 25% milk, then find the concentration of milk in the resulting solution. a. 21% b. 22% c. 23% d. 24% 30 20 207. 7 20 30 -25 20 -20 2020 2b 21-20


  7. If 30 litre of 20% milk is mixed with 20 litre of 25% milk, then find the concentration of milk in the resulting solution. a. 21% b. 22% c. 23% d. 24% First Part Second Part Final Part 30 3 207. 2. 50 25% 23 Cub) 2 Py


  8. Two types of steel A & B are available. Type A contains 5 % Nickel and type B contains 40% Nickel. Quantity of steel B should be mixed with 20 kg of steel A so that the final alloy contains 30% Nickel? a. 20 kg b. 30 kg c. 40 kg d. 50 kg


  9. Two types of steel A & B are available. Type A contains 5 % Nickel and type B contains 40% Nickel. Quantity of steel B should be mixed with 20 kg of steel A so that the final alloy contains 30% Nickel? a. 20 kg b.30 kg c. 40 kg d. 50 kg 5y Ltoy 20 20 40-3 BoV


  10. Two types of steel A & B are available. Type A contains 5 % Nickel and type B contains 40% Nickel. Quantity of steel B should be mixed with 20 kg of steel A so that the final alloy contains 30% Nickel? a. 20 kg b.30 kg c. 40 kg d. 50 kg (hekod-i First Part Second Part Final Part A. 20