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24.
[1
यदि A = | 0
1
1
1
- 2 1
अतः निम्न समीकरण निकाय को हल कीजिए:
x + y + z = 6,
y + 3z = 11
तथा x – 2y + z = 0
1
If A = | 0
1
1
3 है, तो A - 1 ज्ञात कीजिए ।
प्रारंभिक रूपांतरणों द्वारा, निम्नलिखित आव्यूह का व्युत्क्रम ज्ञात कीजिए :
2 3 1
A = 2
1
1
- 2
अथवा
3 7
4 1
A = 2
2
1
3 find A−1.
1
Hence, solve the following system of equations :
x + y + z = 6,
y + 3z = 11
and x - 2y + z = 0
OR
Find the inverse of the following matrix, using elementary
transformations :
2 3 1
4 1
3 7 2

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