“Any linear circuit involving numerous voltages and resistances can be replaced by just one single voltage in series with a single resistance connected across the load,” according to Thevenin’s Theorem. To put it another way, any electrical circuit, no matter how complicated, can be reduced to a two-terminal equivalent using only a single constant voltage source in series with a resistance (or impedance) coupled to a load.
The three most essential components of electricity are voltage, current, and resistance. The link between these three variables is depicted by Ohm’s law. The current flowing through a conductor between two points is proportional to the voltage across the conductor, according to Ohm’s law.
According to Ohm’s law:
V α R
🡺V=IR
Here, V is the voltage or potential difference across resistor R and I is the current flowing through the resistor.
Ohm’s law can be used to determine the voltage, current, impedance, or resistance of a linear electric circuit when the other two quantities are known.
Ohm’s Law’s main applications include:
According to Thevenin’s Theorem, any sophisticated network can be replaced by a voltage source with one resistance in series across its load terminals. When the resistance of a branch is changed while the rest of the network remains the same, this theorem aids in the analysis of current variation in that branch.
Let us consider the above DC circuit for applying Thevenin’s theorem.
We will be measuring the current flowing through the 40 resistor.
To begin analysing the circuit, we must first remove the central 40-ohm load resistor connected across terminals A-B, as well as any internal voltage source resistance (s). This is accomplished by shorting out all of the circuit’s voltage sources, resulting in v = 0, or by open circuiting any associated current sources, resulting in I = 0. The reason for this is that for circuit analysis, we need an ideal voltage source or an ideal current source.
Calculating the equivalent resistance looking back from the terminals A and B with all the voltage sources shorted yields the equivalent resistance, RS. The circuit after that is as follows.
The equivalent resistance will be: RS=10×2010+20=6.67
Now, we will calculate the equivalent voltage.
The current flowing through the circuit will be:
I=VR
🡺I=20-1010+20=0.33A
Voltage across AB will be:
VAB=20-20×0.33=13.33V
Now, the Thevenin equivalent circuit will be:
Therefore, the current flowing through the 40 resistor will be:
I=VR
🡺I=13.3346.67=0.286A
While Thevenin’s circuit theorem can be expressed mathematically in terms of current and voltage, it is less powerful in larger networks than Mesh Current Analysis or Nodal Voltage Analysis. However, Mesh or Nodal analysis is usually required in any Thevenin exercise, so it might as well be used right away. Thevenin’s equivalent circuits of transistors, voltage sources such as batteries, and other components, on the other hand, are extremely valuable in circuit design.