The Stokes’ Law was discovered by Sir George Gabriel Stokes. He was an English scientist. Stokes’ Law is a mathematical equation that was derived to calculate the drag force.
Stokes’ Law states that the force acting on a particle sinks the particle in the fluid medium under the influence of gravity. The force is directly proportional to the velocity, fluid viscosity, and the radius of the sphere.
The force is mathematically given as:
Frv
F=6 rv
Where is the fluid viscosity, r is the radius of the sphere, and v is the sphere’s velocity.
The following assumptions are made while using the Stokes’ equation:
Example 1: A solid ball is falling in a liquid medium that has a terminal velocity of 10 m/s. What is the value of force if the radius of the ball is 5 cm and the viscosity is 1/ kg/ms?
Solution:
Given
The radius of the sphere = 5 cm = 0.05 m
The viscosity of the fluid = 1/ kg/ms
The terminal velocity = 10 m/s
We know that the force is given by the Stokes’ Law.
F=6rv
F=610.0510
F=60.0510
F=3 N
Thus, the value of the drag force is 3 Newtons.
Example 2: The value of the drag force is 6 N. Find the value of terminal velocity if the sphere of the radius is 20 cm and the viscosity of the fluid is 0.5 kg/ms.
Solution:
Given
The radius of the sphere = 20 cm = 0.2 m
The viscosity of the fluid = 0.5 kg/ms
The drag force = 6 N
We know that the velocity is given by the Stokes’ Law.
F=6rv
6=60.20.5v
v=10.20.5
v=10 m/s
The applications of the Stokes’ Law are given as follows:
The limitations of the Stokes’ Law are as follows:
Stoke’s Law of Sedimentation states that the terminal velocity of the sediment particle is directly proportional to the square of particle diameter, the difference between the density of the particle and liquid phase and inversely proportional to the viscosity of the liquid.
vd2(p–f)
v=gd2(p–f)18
Where
p is the density of the particle
f is the density of the liquid
is the viscosity of the liquid
d is the diameter of the particle
g is the acceleration due to gravity
Example 1: What is the viscosity of the liquid if the density of the solid ball is 8050 kg/m3, the diameter of the particle is 0.1 m, and the terminal velocity is 10 m/s? Assume the density of the fluid is 1000 kg/m3 and g = 10 m/s2.
Solution:
Given
The terminal velocity (v) = 10 m/s
The density of the particle (p) = 8050 kg/m3
The density of the liquid (f) = 1000 kg/m3
The diameter of the particle (d) = 0.1 m
We know that the Stokes’ Law of Sedimentation will be:
v=gd2(p–f)18
Then, the viscosity of the fluid is given as:
=gd2(p–f)18v
If we put all the values in the above equation, we have the following:
=100.12(8050-1000)1810
=100.017050180
= 705180
=3.92 kg/ms
Some precautions are given as follows:
Using the Stokes’ Law, we can predict the settling velocity of particles of different sizes. The large grain settles faster than the small size grain. Stokes’ Law of Sedimentation is generally used to calculate the value of the terminal velocity, but we can also calculate the value of the viscosity of the fluid.