A Triangle is basically a polygonal structure that has three edges, three angles, and three respective vertices.
On the basis of angles, we can classify triangles into:
Properties of Triangle is an essential item in the study of Geometry. It is crucial to have a full-fledged understanding of its properties so that it can be effectively applied while dealing with practical problems.
In a triangle ABC,
∠A +∠B +∠C =180º.
2.As per the theorem of triangle inequality the sum of the length of any two sides has to be greater in a triangle.
In a triangle ABC,
a+b>c,
b+c>a,
c+a>b.
3.The side which lies right opposite to the greater angle will be the longest side of the triangle.
In a triangle ABC,
If ∠B is the greatest angle, the side opposite to it i.e., AC will be the longest side.
4.The Pythagoras property or what is commonly known as the Pythagoras theorem states that the square of the hypotenuse will be equal to the sum of the square of the two other sides in a right-angle triangle.
Base² + Height²= Hypotenuse².
5.The congruence property of a triangle states that all the corresponding sides, as well as all the angles, must be equal for a triangle to be congruent.
If we take two triangles, say ABC and XYZ, then,
∠ABC=∠XYZ.
∠BAC=∠YXZ.
∠CAB=∠ZXY.
AB=XY.
AC=XZ.
BC=YZ.
6.The exterior angle of a triangle is the sum total of the angles of the two opposite interior angles.
If the exterior angle is e and the interior angles are a,b,c, then
∠e=∠a+∠b.
Has two sides of equal length and the other side is of different length.
Property 1:
Example:
Find the value of x if (x-10), xº and (x+40)ºrepresent three interior angles of a triangle.
Solution:
We know that,
Sum of all the three angles = 180º.
Let the sides of the triangle XYZ be XY=(x-10)º, YZ=xºand ZX=(x+40)º.
According to the problem,
(x-10)º+ xº+ (x+40)º=180º.
= 3x+30º=180º.
=3x=180º-30º.
=3x= 150º.
=x=150º/3=50º.
Thus, the value of x= 50º.
Putting the value of x in,
(x-10)º=50º-10º=40º.
(X+40)º=50º+40º=90º.
Thus, 50º+40º+90º=180º.
Property 2: Triangle Inequality
Example:
3 units, 4 units, and 5 units are the respective lengths of three sides of a triangle. Prove that it satisfies the triangle inequality property.
Solution:
Let ABC be a triangle, where
AB= 5 units, BC=3 units, and CA=4 units.
According to the theorem, the length of any two sides should be greater than the third side.
Therefore, AB+CA>BC
= 5 units+ 4units> 3 units.
AB+ BC > CA
= 5 units+ 3 units> 4 units.
BC+CA>AB
= 3 units+ 4 units > 5 units .
Thus, the above example satisfies the triangle inequality theorem.
Property 3: Pythagoras Theorem
Example:
The length of the sides of a triangle are 5cm, 4cm, and xcm. Find x.
Solution
According to pythagoras theorem,
Hypotenuse²=Base²+Height².
Let us assume ABC as a triangle, where, AB= 5cm, BC= xcm, and CA=4 xcm.
Therefore, (CA)²=(AB)²+ (BC)².
= 4²=5²+x².
= x²= 25-16
=x= √9
= x= 3 cm.
The properties of triangles help us determine unknown quantities in geometry and trigonometry.
They are usually applied in fields such as construction, navigation astronomy, and architecture.
They cover an entire gamut of geometrical properties and help us solve complex problems in various fields.