In two-dimensional coordinate geometry, each point in two-dimensional space is assigned with unique coordinates used to identify the point in the plane or graph.
Two Dimensions – Distance of a Point from a Line represents the distance (denoted by d) between any point P (x1, y1) and a line L whose equation is ax + by + c = 0, lying in a 2D plane.
Two Dimensions – Distance of a Point from a Line is given by the expression –
d = [|ax1 + by1 + c| / √ (a2 + b2)]. It represents the distance (denoted by d) between any point P (x1, y1) and a line L whose equation is ax + by + c = 0, lying in a 2D plane.
d = [|ax1 + by1 + c| / √ (a2 + b2)].
Assume a line L represented by the equation Ax + By + C = 0, and a point N (x1, y1) lying in an XY Plane. The perpendicular distance of point N to line L is ‘d = NM’, which equals the perpendicular length drawn to line L. The x and y-intercepts for the given line are (-C/A) and (-C/B), respectively.
From the above figure, we can see that the line L meets the x and y axes at points B and A respectively and their coordinates are A (x3, y3) = A (0, -C/B) and B (x2, y2) B (-C/A, 0). The area of /\NAB is given by:
Area (/\NAB) = ½ x Base x Height = ½ (AB) (NM)
AB
We also know that area of /\NAB can be given by –
Area (/\NAB) = ½ | x1(y2 − y3) + x2(y3 − y1) + x3(y1 − y2) |
= ½ | x1 (0 + C/B) + (−C/A) (−C/B − y1) +0 (y1 − 0) |
= ½ | x1 C/B + y1 C/A + C2/AB |
= ½ |C/(AB) |. |Ax1 + By1 + C| – eq. 2
We know that distance AB = √ [(0 + C/A)2 + (C/B − 0)2] = |C| x √ [(1/A2) + (1/B2)]
= |C/AB|. √ (A2 + B2) -eq. 3
Putting values of eq. 2 and eq. 3 in eq. 1, we get,
NM = d = [|Ax1 + By1 + C| / √ (A2 + B2)], which is the two dimensions – distance of a point from a line in analytical geometry.
Through this article on Analytical Geometry – Two Dimensions – Distance of a Point from a Line – Maths, students can understand and grasp the concepts of analytical or coordinate geometry and its applications, two-dimensional (or 2-D) coordinate system, as well as the formula and derivation of two dimensions – distance of a point from a line.
Two Dimensions – Distance of a Point from a Line represents the distance (denoted by d) between any point P (x1, y1) and a line L whose equation is ax + by + c = 0, lying in a 2D plane, and it is expressed as: d = [|ax1 + by1 + c| / √ (a2 + b2)].