A first-order differential equation is an ordinary differential equation in which any derivatives with respect to the independent variable have an order less than 1. If the variables m and n can be separated then a first-order equation is said to be separable. By separating the variables and then integrating both sides of the equation with respect to m, one can solve such equations.
A differential equation of type
n’ + a(m)n = f(m),
Where,
an (m) and f(m) are continuous functions of m, which is called a linear equation of first order. Linear equation of first order can be solved by using two methods:
At first, one need to find the general solution of the homogeneous equation:
n’ + a (m)n = 0
The general solution of the homogeneous equation contains a constant of integration C. The constant integer C needs to be replaced with a certain function C (m). By substituting this solution into the non-homogeneous differential equation, one can determine the function C (m).
When a differential linear equation is portrayed in a standard form:
n’ + a (m)n = f(m),
Then the factor integrated in defined by the given formula
u (m) = exp (⌠a (m)dm
By multiplying the equations of the left-hand side of the equation by the integrating factor u (m) converts the left side into the derivative of the product n (m) u (m).
The differential equation’s general solution is expressed as follows:
n = ⌠u (m) f(m) dm + C / u (m)
C is the arbitrary constant
Although there is no general method for the solution is available for first-order nonlinear equations, there are several cases of physically relevant nonlinear equations which can be solved analytically:
dn / dm = f(m) / g(n)
For example:
dn / dm = n2ex
Or,
n = -1 / (ex + c)
dn /dm = f(am + bn)
Change variables:
z = am + bn
For example:
Dn / dm = (-4m + n) 2
Z = n – 4m
m = ¼ ln(z-2 / z+2) + C
dn / dm = f (n / m)
The equation is invariant under m→ sm, n→ sn
Solution
n = vm
i.e. v’ = 1 / m {f(v) –v}
For example:
mn (dn/dm) – n2 = (m + n)2e-n/m
Change variables
n = vm
(v’m + v) – v = {(1 + v)2 / v } e-v
To evaluate integral change variables
u = 1+ v
e-1 ⌠(1/u – 1/u2)eu du = e-1[eu/u]
i.e ln m = en/m / (1+ n/m)
dn / dm = m+ 2n + 1 / x + y+ 2
m = m’ + a, n = n’ +b
[1+a+2b = 0 and 2+a+b=0]
[a = -3 and b = 1]
dn / dm + P(m)n = Q(m)yn, n≠1
T solve, change variable to
z = n1-n
Gives the equation [dz /dm + (1-n)P(m)z = (1 – n)Q(m)] {First Order Linear}
For example:
n’+n= y2/3
z = y1-n = n1/3
Integrating factor em/3
∴ z = n1/3 = 1 + ce-x/3
This is to conclude that a first-order differential equation is an ordinary differential equation in which any derivatives concerning the independent variable have the order of less than 1. If the variables m and n can be separated then a first-order equation is said to be separable. By separating the variables and then integrating both sides of the equation with respect to m, one can solve such equations.