Permutations are a method to determine the number of all possible arrangements of a set of elements. The arrangement of elements is significant, and the arrangement of elements is made by applying certain restrictions.
Restricted permutations are permutations where certain elements are always either included or excluded. In addition to this, it also refers to the permutations that can either always occur together or always stay apart.
NOTE:- nPr = n! / (n – r)!
Example:
Find out how many three digits numbers without any repetition can be made using 1, 2, 3, 4, 5 if one will always be there in the number.
Solution:
Here, we will use the formula: r x n-1Pr-1
It is given that, r = 3
n = 5
Now by putting the values of r and n in the formula r x n-1Pr-1
We get,
= 3 x 5-1P3-1
= 3 x 4P2
= 3 x (4! / (4-2)!)
= 3 x [(4 x 3 x 2!) / 2!]
= 3 x (4 x 3)
= 3 x 12
= 36
Therefore, 36 three digits numbers can be made where one will always be included in the
number.
Example:
Find out how many three digits numbers without any repetition can be made using 1, 2, 3, 4, 5 if 1 will never be there in the number.
Solution:
Here, we will use the formula: n-1Pr-1
It is given that r = 3
n = 5
Now, by putting the values of r and n in the formula n-1 P r
We get:
= n-1Pr
= 5-1P3
= 4P3
= (4! / (4-2)!)
= [(4 x 3 x 2!) / 2!]
= (4 x 3)
= 12
Therefore, 12 three-digit numbers can be made wherein 1 will never be there in the number.
Here we have learnt how to deal with restricted permutations, wherein we have to permutate according to the conditions given. Such problems can be solved by using basic concepts of permutations and combinations, along with some logical approaches.