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GATE Relevant Geometry Questions: Part 1
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Overview and Introduction

Deep Sangeet Maity
->YOUTUBER (THE GATE RANKER) ->DESIGN ENGINEER @ SCHLUMBERGER ->KREATRYX GATE Content Developer ->99.4%ile GATE

Unacademy user
mam please tell me how u prepare your sociology optional
will you please do videos for npcil interview videos sir
sir will u please videos for npcil interview if possible
hello sir I have jus started preparing my gate. I started with my favorite td but sir should I read two subjects daily or I should complete one and then go for other? should I start doing numericals now itself or after completion of my theory part. first time preparing for gate sir, so pls suggest me
sir plss start GATE 2020 General aptitude
Naveen Pawar
2 months ago
daily lesson
  1. General Aptitude Geometry & Mensuration Questions for GATE Presented by Deep sangeet Maity


  2. About ME Working as a Design engineer at "Cameron Manufacturing India Limited (A Schlumberger Company)". Currently working as "GATE content editor and developer" at "Kreatryx". .Qualified GATE "4" times . Qualified "Gate 2018 with 99.4 percentile 779(75.26 marks) gate score" in mechanical stream. Qualified "Gate 2017 with 98.83 percentile 726(70 marks) gate score" in mechanical stream I also have an 3+ years of experience of teaching Engineering subjects like Engineering mechanics, Thermodynamics, SOM, HMT. Ex-CADD Engineer at "CADD CENTRE". Passed B.E. with honours with 76.71%. I am pursuing my MTech in Thermal. I have an 2.5+ years of experience as a CADD Engineer. .I also have worked for "CAD ACADEMY" as a Design engineer for 1 year.


  3. Target audience Gate aspirants(All branches


  4. Objectives To clear the numerical based concepts. To give the shortcut tricks for solving questions wherever is required. At last, to clear the competitive exam by the aspirants.


  5. PgRS is a quarensibed nHhe oute circle. it o Points penimetr Ca)



  6. Peni meter Perimeten ctrcle be .


  7. p 3:08 (Square B 90


  8. Now, OB is ehadius of inner. J2-


  9. 0 AB = BC = AD-cD