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In A ABC, AC = 450 and BC = 300. Points K and L are located on AC and AB respectively so that
AK = CK, and CL is the angle bisector of angle C. Let P be the point of intersection of BK and CL,
and let M be the point on BK for which K is the midpoint of PM. If AM = 180, find LP ?
AABC में, AC = 450 और BC = 3001 बिंदू K और L क्रमशः AC और AB पर स्थित हैं ताकि
AK = CK, और CL कोण C का कोण समदविभाजक हो। मान लीजिए कि P, BK और CL का
प्रतिच्छेदन बिंदु है, और मान लें कि M, BK पर स्थित वह बिंदु है, जिसके लिए K, PM का
मध्यबिंदु है। यदि AM = 180 है, तो LP ज्ञात कीजिए।
(a) 90
(b) 81
(c) 72
(d) None of these
A
180)
L
Q
300

Hindi

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