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Reflection & Refraction

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Question 1 of 5

A thin lens focal length f and its aperture has diameter d. It forms an image of intensity I. Now the central part of the aperture up to diameter $\frac{d}{2}$ is blocked by an opaque paper. The focal length and image intensity will change to

$f\ and\ \frac{I}{4}$

$\frac{3f}{4}\ and\ \frac{I}{2}$

$f\ and\ \frac{3I}{4}$

$\frac{f}{2}\ and\ \frac{I}{2}$

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Reflection & Refraction

Quick practice

Question 1 of 5

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