Practice Units & Dimensions - NEET UG Offered by Unacademy

Units & Dimensions

If the radius of the sphere is (5.3±0.1) cm. Then percentage error in its volume will be

$\left(\frac{3 \times 0.1}{5.3}\right) \times 100$

$\left( {\frac{{0.1}}{{5.3}}} \right) \times 100$

$3 + 6.01 \times \left( {\frac{{100}}{{5.3}}} \right)$

$\left( {\frac{1}{3}} \right) \times 0.01 \times \left( {\frac{{100}}{{5.3}}} \right)$