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Inorganic Chemistry

Quick practice

Question 1 of 5

The oxidation state of Sulphur in anion \mathrm{So}_{3}^{2-}, \mathrm{~S}_{2} \mathrm{O}_{4}^{2-} and  \mathrm{S}_{2} \mathrm{O}_{6}{ }^{2-}  follow the order:-

A

\mathrm{S}_{2} \mathrm{O}_{4}^{2-}<\mathrm{S}_{2} \mathrm{O}_{6}^{2-}<\mathrm{So}_{3}^{2-}

B

\mathrm{S}_{2} \mathrm{O}_{6}^{2-}<\mathrm{S}_{2} \mathrm{O}_{4}^{2-}<\mathrm{So}_{3}^{2-}

C

\mathrm{So}_{3}^{2-}<\mathrm{S}_{2} \mathrm{O}_{3}^{2-}<\mathrm{S}_{2} \mathrm{O}_{6}^{2-}

D

\mathrm{S}_{2} \mathrm{O}_{4}^{2-}<\mathrm{So}_{3}^{2-}<\mathrm{S}_{2} \mathrm{O}_{6}^{2-}

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