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Units & Conversion

Quick practice

Question 1 of 5

 A gas mixture analysing 30%(mole) CO, 30%(mole) \mathrm{H}_2 and 40 \%( mole ) \mathrm{N}_2 is burned in air. The following heats of reaction data are available:

\mathrm{CO}+\frac{1}{2} \mathrm{O}_2 \rightarrow \mathrm{CO}_2 \Delta H_r^{\circ}=-282.91 \mathrm{KJ} / \mathrm{mol}

\mathrm{H}_2+\frac{1}{2} \mathrm{O}_2 \rightarrow \mathrm{H}_2 \mathrm{O} \Delta \mathrm{H}_r^{\circ}=-241.83 \mathrm{KJ} / \mathrm{mol}

If only 80% of the CO and 70% of the \mathrm{H}_2 react, how much heat in kJ is liberated on the combustion of 100 mole of the mixture?

A

6789.8

B

5078.4

C

8095.7

D

11868.3

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