Practice Triangles - CBSE Class 10 Offered by Unacademy

Triangles

In the given figure, $\angle A B C=\angle A C B,$ if $\angle ABP=$ $140^{o}$ , find $\angle B A C$

$60^{\circ}$

$50^{\circ}$

$100^{\circ}$

$140^{\circ}$