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Refraction & Refraction of Light

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Question 1 of 5

In Young’s double slit experiment, the $true$ maximum with wavelength $\lambda_{1}$ is at a distance $d_{1}$ from the central maximum and the 6th maximum with a wavelength $\lambda_{2}$ is at a distance $d_{2}$ Then $\left(d_{1} / d_{2}\right)$ is equal to

$\frac{3}{4}\left(\frac{\lambda_{1}}{\lambda_{2}}\right)$

$\frac{3}{4}\left(\frac{\lambda_{2}}{\lambda_{1}}\right)$

$\frac{4}{3}\left(\frac{\lambda_{2}}{\lambda_{1}}\right)$

$\frac{4}{3}\left(\frac{\lambda_{1}}{\lambda_{2}}\right)$

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Refraction & Refraction of Light

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Question 1 of 5

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