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Rigid Body Dynamics

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Question 1 of 5

If the position vector of a particle is $\vec{r}=(3 \hat{i}+4 \hat{j})$ meter and its angular velocity is $\vec{\omega}=(\hat{j}+2 \hat{k})$ sec then its linear velocity is (in m/s)

$(8 \hat{i}-6 \hat{j}+3 \hat{k})$

$-(3 \hat{i}+6 \hat{j}+6 \hat{k})$

$(3 \hat{i}+6 \hat{j}+8 \hat{k})$

$(6 \hat{i}+8 \hat{j}+3 \hat{k})$

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Rigid Body Dynamics

Quick practice

Question 1 of 5

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SELF STUDY

Rigid Body Dynamics

Quick practice

Question 1 of 5

Get unlimited practice with IIT JEE subscription

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