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Kinematics

Quick practice

Question 1 of 5

The position of a particle as a function of time t, is given as, \mathrm{x}(\mathrm{t}) \Rightarrow 5 \mathrm{t}^{3}-25 \mathrm{t}^{2}+4 \mathrm{t}. Find the velocity of the particle when its acceleration becomes zero.

A

-16

B

\frac{113}3

C

16

D

-\frac{113}3

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