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IIT JEE

Practice

Modern Physics

Photoelectric Effect

Quick practice

Question 1 of 5

The binding energies of nuclei X and Y are

\mathrm{E}_{1}   and \mathrm{E}_{2} respectively. Two atoms of X fuse to give one atom of Y and an energy Q is released then

A

\mathrm{Q}<2 \mathrm{E}_{1}-\mathrm{E}_{2}

B

\mathrm{Q}=2 \mathrm{E}_{1}-\mathrm{E}_{2}

C

\mathrm{Q}=\mathrm{E}_{2}-2 \mathrm{E}_{1}

D

\mathrm{Q}>\mathrm{E}_{2}-2 \mathrm{E}_{1}

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