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IIT JEE

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Capacitance

Concept of Capacitance

Quick practice

Question 1 of 5

Five conducting parallel plates having area A and separation between them d, are placed as shown in the figure. Plate number 2 and 4 are connected by wire and between point A and B, a cell of emf E is connected. The charge flown through the cell is

A

\frac{3}{4} \frac{\varepsilon_0 \mathrm{AE}}{\mathrm{d}}

B

\frac{2}{3} \frac{\varepsilon_0 \mathrm{AE}}{\mathrm{d}}

C

\frac{\varepsilon_0 A E}{2 d}

D

\frac{4 \varepsilon_0 A E}{d}

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