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IIT JEE

Practice

Physical Chemistry

General Topics & Mole Concept

Quick practice

Question 1 of 5

EMF of a cell in terms of reduction potential of its left and right electrodes is -

A

\mathrm{E}=\mathrm{E}_{\mathrm{left}}-\mathrm{E}_{\mathrm{right}} 

B

\mathrm{E}=\mathrm{E}_{\mathrm{right}}-\mathrm{E}_{\mathrm{left}}

C

\mathrm{E}=\mathrm{E}_{\mathrm{left}}+\mathrm{E}_{\mathrm{right}} 

D

\mathrm{E}=-(\mathrm{E}_{\mathrm{right}}+\mathrm{E}_{\mathrm{left}})

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