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Fluid Mechanics

Quick practice

Question 1 of 5

A mercury drop of radius 10^{-3} m is broken into 125

equal size droplets. Surface tension of mercury is

0.45 \mathrm{Nm}^{-1}. The gain in surface energy is:

A

28 \times 10^{-5} \mathrm{~J}

B

2.26 \times 10^{-5} \mathrm{~J}

C

17.5 \times 10^{-5} \mathrm{~J}

D

5 \times 10^{-5} \mathrm{~J}

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