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CSIR-UGC NET

Practice

Complex Analysis

Preliminaries

Quick practice

Question 1 of 5

The bilinear transformation which maps the points z_{1}=2, z_{2}=i   and z_{3}=-2 into the points w_{1}=1, w_{2}=i   and w_{3}=-1  respectively is

A

w=\frac{z^{2}}{2}

B

w=\frac{3 z+2i}{iz-6}

C

w = iz

D

w = 0

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