Practice Standard Equation of Circles - Class 11th Hindi Medium Offered by Unacademy

Standard Equation of Circles

The line joining the points (2,5) and (6,1) represents the diameter of a circle. Find the equation of the circle.

$x^{2}+y^{2}-4 x-3 y+11=0$

$x^{2}+y^{2}-8 x-6 y+17=0$

$x^{2}+y^{2}-5 x-y+8=0$

$x^{2}+y^{2}-2 x-6 y+3=0$